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-5x^2+75x-130=0
a = -5; b = 75; c = -130;
Δ = b2-4ac
Δ = 752-4·(-5)·(-130)
Δ = 3025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3025}=55$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(75)-55}{2*-5}=\frac{-130}{-10} =+13 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(75)+55}{2*-5}=\frac{-20}{-10} =+2 $
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